MHT CET Chemistry question
How many grams of sulphuric acid is to be dissolved to prepare 200 mL aqueous solution having concentration of ions 1M at 25 ℃ temperature? [H = 1, O = 16, S = 32 g mol]
Answer: (C)
Solution
(taken as fully ionised) gives 2 per molecule, so 1 M needs 0.5 M acid; moles = 0.5 × 0.2 = 0.1 mol = 0.1
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