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MHT CET Chemistry question

ChemistrySolutionsMHT CET

At 80 ℃, the vapour pressure of pure liquid 'A' is 520 mmHg and that of pure liquid 'B' is 1000 mm Hg. If a mixture solution of 'A' and 'B' boils at 80 ℃ and 1 atm pressure, the amount of 'A' in the mixture is (1 atm = 760 mm of Hg)

Answer: (D)

Solution

Boiling at 1 atm means total vapour pressure = 760 mm Hg: gives , so

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Question ID VK-061265