MHT CET Chemistry question
The vapour pressure of water at is 17.5 mmHg. If 18 g of glucose () is added to 178.2 g of water at , the vapour pressure of the resulting solution will be
Answer: (D)
Solution
Glucose = 18/180 = 0.1 mol and water = 178.2/18 = 9.9 mol, so and $p = 17.5×0.99 =
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