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MHT CET Chemistry question

ChemistrySolutionsMHT CET

9 gram anhydrous oxalic acid (mol. wt. = 90) was dissolved in 9.9 moles of water. If vapour pressure of pure water is the vapour pressure of solution is [MHTCET 2019]

Answer: (A),(C)

Solution

Moles of oxalic acid = 9/90 = 0.1 mol, so and (options a and c state

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Question ID VK-061391