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MHT CET Physics question

PhysicsSystems of Particles and Rotational MotionMHT CET

A uniform metal disc of radius R is taken and out of it a disc of diameter R is cut-off from the end. The centre of mass of the remaining part will be

Answer: (D)

Solution

Removed disc has radius R/2, area with CM at R/2; remaining area , so \dfrac{(π R^2/4)(R/2)}{3π R^2/4}$

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Question ID VK-062401