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MHT CET Physics question

PhysicsThermal Properties of MatterMHT CET

Two bodies A & B have thermal emissivity's of the 0.16 & 0.81 resp. The outer surface areas of two bodies are same. The two bodies emit total radiant power at same rate. If the temp of A is 5802 K, then temperature of B is

Answer: (A)

Solution

Equal power gives , so $ = 5802×(0.16/0. = 5802× =

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Question ID VK-063082