MHT CET Physics question
Rate of cooling of body is 0.5℃/min, when the system is 50℃ above the surroundings. When a system is 30℃ above the surroundings, the rate of cooling will be [MH-CET 2004]
Answer: (A)
Solution
Rate of cooling , so rate $= 0.5 × 30/50 =
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