MHT CET Physics question
100 g of water is heated from 30℃ to 50℃ ignoring the slight expansion of the water, the change in its internal energy is (specific heat of water is 4184 J/Kg/K)
Answer: (B)
Solution
With negligible expansion the work done is zero, so $Δ U = mcΔ T = 0.1 × 4184 × 20 ≈ 8368\ J
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