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MHT CET Chemistry question

ChemistryThermodynamicsMHT CET

Enthalpy of vapourization of naphthalene is 48.5 , enthalpy of fusion of naphthalene is 22.5 , then enthalpy of sublimation of naphthalene will be equal to

Answer: (D)

Solution

Sublimation = fusion + vaporization = 22.5 + 48.5 = 71.0 kJ/mol (Hess's law); (c)

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Question ID VK-064206