MHT CET Chemistry question

If the heat of neutralization of a strong acid with strong base is -57 kJ, the same for 0.1 N, with 0.3 N, NaOH is

Answer: (A)

Solution

The heat of neutralization is -57 kJ per equivalent of H neutralised; taking 1 L of the 0.1 N acid, 0.1 equivalent reacts (NaOH is

Create a free account to read the complete working, and practise questions like this in a timed test.

Question ID VK-064229