Given the reaction, N_ 2(g) + 3H_ 2(g) 2NH_ 3(g) , H = -92.6 kJ. The enthalpy of formation of NH_3 is

MHT CET Chemistry question

Given the reaction, , kJ. The enthalpy of formation of is

Answer: (C)

The given reaction forms 2 mol NH, so the enthalpy of formation per mole is -92.6/2 = -46.3 kJ/mol;

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Question ID VK-064269