MHT CET Chemistry question
3 moles of an ideal gas is compressed from 30 to 20 against a constant pressure of . The work done in calories is . (1 J = 0.239 cal)
Answer: (C)
Solution
W = -p = -(3.039 x -10 x = +3039 J = 3039 x 0.239 = +726.3 cal;
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