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MHT CET Chemistry question

ChemistryThermodynamicsMHT CET

When 2 moles of are completely burnt, 3129 kJ of heat is liberated. If for and are and kJ per mole respectively. The heat of formation of is

Answer: (B)

Solution

Combustion enthalpy per mole = -3129/2 = -1564.5 kJ = [2(-395) + 3(-286)] - (C2H6) = -1648 - , so

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Question ID VK-064484