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MHT CET Chemistry question

ChemistryThermodynamicsMHT CET

Given: (i) , kJ (ii) , kJ (iii) , kJ (iv) , kJ Then the enthalpy of formation of at 298 K will be

Answer: (A)

Solution

Adding (i) + (ii) + (iii) + (iv) gives S + H2 + 2O2 -> H2SO4 (H2O cancels), so = -298.2 - 98.7 -

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Question ID VK-064486