MHT CET Chemistry question

ChemistryThermodynamicsMHT CET

In the combustion of 2.0 g of methane 25 kcal heat is liberated, heat of combustion of methane would be

Answer: (B)

Solution

2.0 g of CH4 is 2/16 = 0.125 mol, so heat per mole = 25/0.125 = 200 kcal (liberated); the

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Question ID VK-064489