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MHT CET Chemistry question

ChemistryThermodynamicsMHT CET

Given the bond energies N≡N, H-H and N-H bonds are 945, 436 and 391 respectively, the enthalpy of the following reaction is

Answer: (A)

Solution

= energy of bonds broken - energy of bonds formed = (945 + 3 x 436) - (6 x 391) = 2253 - 2346 = -93 kJ;

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Question ID VK-064493