MHT CET Chemistry question
The heat of neutralization of HCl by NaOH under certain condition is kJ and that of HCN by NaOH is kJ. The heat of ionization of HCN is [MP PET 2001]
Answer: (D)
Solution
H_{ion}(H_{neut}(H_{neut}($strong\ acid) = -12.1 - (-55.9) = +43.8\
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account