MHT CET Chemistry question

Chemistry Thermodynamics MHT CET

kcal

kcal

The heat of formation of CO(g) is

(A) kcalCorrect
(B)41.2 kcal
(C)26.4 kcal
(D)229.2 kcal

Answer: (A)

Solution

Subtract half of the second equation from the first: , $Δ H = -94 - (-135.2/2) = -94

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Question ID VK-064746