The value of n in the following equation is Cr_2O_7^ 2- + 14 H^+ + n Fe^ 2+ 2 Cr^ 3+ + n Fe^ 3+ + 7 H_2O

MHT CET Chemistry question

The value of n in the following equation is \mathrm{Cr_2O_7^{2-}} + 14H^+ + n\mathrm{Fe^{2+}} \longrightarrow 2\mathrm{Cr^{3+}} + n\mathrm{Fe^{3+}} + 7H_2O

(A)4
(B)3
(C)7
(D)6Correct

Answer: (D)

Solution

Two Cr(+6) to Cr(+3) accept 6 electrons and each gives 1, so n = 6 (charge

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Question ID VK-065848