MHT CET Chemistry question
The oxidation number of Cr in is
Answer: (C)
Solution
2(+1) + 2x + 7(-2) = 0 gives 2x = 12 so x = +6; +2, +4 and +7 do not satisfy the neutrality condition. Hence the correct option is (c).
The oxidation number of Cr in is
2(+1) + 2x + 7(-2) = 0 gives 2x = 12 so x = +6; +2, +4 and +7 do not satisfy the neutrality condition. Hence the correct option is (c).