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MHT CET Physics question

PhysicsThermal Properties of MatterMHT CET

A beaker contains 200 g of water. The heat capacity of the beaker is equal to that of 20 g of water. The initial temperature of water in the beaker is . If 440 g of hot water at is poured in it, the final temperature (neglecting radiation loss) will be nearest to

Answer: (B)

Solution

Heat lost = heat gained: , so \dfrac{220×20+440×92}{660}$ =

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Question ID VK-065899