MHT CET Chemistry question
What weight of copper will be deposited by passing 2 Faraday of electricity through a solution of copper sulphate?
Answer: (A)
Solution
2 F is 2 gram equivalents, i.e. 1 mol of Cu, which is 63.5 g; 31.75 g is for 1 F and 127.0 g is for 4 F. Hence the correct option is (a).