For the reaction Zn(s) + Cu^ 2+ → Zn^ 2+ (aq) + Cu(s), Nernst equation at 25°C is

MHT CET Chemistry question

For the reaction Zn(s) + Cu → Zn(aq) + Cu(s), Nernst equation at 25°C is

(A)E = E^\circ - \frac{0.059}{2}\log\frac{[\mathrm{Zn^{2+}(aq)}]}{[\mathrm{Cu^{2+}(aq)}]}Correct
(B)E = E^\circ - \frac{0.059}{2}\log\frac{[\mathrm{Zn^{2+}(aq)}]}{[\mathrm{Zn^{2+}(aq)}]}
(C)E = E^\circ - \frac{0.059}{2}\log\frac{[\mathrm{Cu^{2+}(aq)}]}{[\mathrm{Zn^{2+}(aq)}]}
(D)E = E^\circ - \frac{0.059}{2}\log\frac{[\mathrm{Cu^{2+}(aq)}]}{[\mathrm{Cu^{2+}(aq)}]}

Answer: (A)

For the cell reaction n = 2 and Q = [products]/[reactants] = [Zn]/[Cu] (solids have unit activity), so E = E - (0.059/2) log

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Question ID VK-066330