MHT CET Chemistry question
If standard electrode potential of Cu / Cu is 0.34 V, then potential of Cu dipped in 0.1 M solution of CuSO will be
Answer: (C)
Solution
E = E + (0.059/2) log [Cu] = 0.34 + 0.0295 × log 0.1 = 0.34 - 0.0295 ≈ 0.31 V; 0.34
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