The emf for the cell Ni | Ni^ 2+ (1.0 M) || Au^ 3+ (1.0 M) | Au (E^ for Ni^ 2+ / Ni = -0.25 V; E^ for Au^ 3+ | Au = 1.50 V) is

MHT CET Chemistry question

The emf for the cell Ni | Ni (1.0 M) || Au (1.0 M) | Au ( for Ni/ Ni = -0.25 V; for Au | Au = 1.50 V) is

Answer: (C)

E = E - E = 1.50 - (-0.25) = 1.75 V (emf is an intensive property, so the electrode potentials are not multiplied by

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Question ID VK-066358