Given that E^ (Zn) = -0.76 V and E^ (Mg | Mg^ 2+ ) = 2.37 V. What will happen when zinc dust is added to MgCl_2 solution?

MHT CET Chemistry question

Given that E(Zn) = -0.76 V and E(Mg | Mg) = 2.37 V. What will happen when zinc dust is added to MgCl solution?

Answer: (D)

For Zn + Mg → Zn + Mg, E = E(Mg) - E(Zn) = -2.37 - (-0.76) = -1.61 V, which is negative,

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Question ID VK-066395