MHT CET Chemistry question
The resistance of 0.01 N NaCl solution at 25℃ is 200 Ω. Cell constant of conductivity cell is . The molar conductance is [CBSE PMT 1999]
Answer: (A)
Solution
κ = cell constant/R = 1/200 = 0.005 S ; Λ = κ × 1000/C = 0.005 × 1000/0.01 = 500 = 5
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