MHT CET Chemistry question
The limiting molar conductivities for NaCl, KBr and KCl are 126, 152 and 150 respectively. The for NaBr is [AIEEE 2004]
Answer: (C)
Solution
By Kohlrausch's law Λ°(NaBr) = Λ°(NaCl) + Λ°(KBr) − Λ°(KCl) = 126 + 152 − 150 = 128; 278 (126 +
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