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MHT CET Chemistry question

ChemistryElectrochemistryMHT CET

The emf of the following cell, \mathrm{Zn|ZnSO_4(1\,M)||H^+(1\,M)|H_{2(g)}(1\,atm)|Pt} is 0.769 volts. The reduction potential of Zn electrode will be [MH CET 2001]

Answer: (B)

Solution

E°cell = E°/H2) − E°+/Zn) = 0 − E°+/Zn) = 0.769, so the reduction potential of Zn is

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Question ID VK-066767