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MHT CET Chemistry question

ChemistryElectrochemistryMHT CET

Given below are the half-cell reactions: ; E° = −1.18 V and ; E° = +1.51 V. The E° for will be [JEE (MAIN) 2014]

Answer: (A)

Solution

Reduction half is +/Mn (−1.18 V) and oxidation half is + → + (−1.51 V), so E° = −1.18 − 1.51 = −2.69

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Question ID VK-066770