MHT CET Chemistry question
Given V, V. The potential for the cell \mathrm{Cr|Cr^{3+}(0.1\,M)||Fe^{2+}(0.01\,M)|Fe} is
Answer: (D)
Solution
E° = −0.42 + 0.72 = 0.30 V; for 2Cr + + → + + 3Fe, n = 6 and Q = (0./(0. = , so E = 0.30 − (0.0591/6) × 4 = 0.30 −
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