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MHT CET Chemistry question

ChemistryElectrochemistryMHT CET

The electrode potentials for and are +0.15 V and +0.50 V respectively. The value of will be

Answer: (C)

Solution

Adding the two steps, 2FE° = FE1 + FE2, so E° = (0.15 + 0.50)/2 = 0.325 V; (a) and (b) are the

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Question ID VK-066780