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MHT CET Chemistry question

ChemistryElectrochemistryMHT CET

The value of for , NaOH and NaCl are respectively 149.74, 248.1 and 126.4 . The value of of is

Answer: (B)

Solution

Missing close braceΛ^∞(\mathrm{NH_4OHExtra close brace or missing open brace}) = Λ^∞(\mathrm{NH_4Cl$}) + Λ^∞(NaOH) - Λ^∞(NaCl) = 149.74 +

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Question ID VK-066862