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MHT CET Chemistry question

ChemistryElectrochemistryMHT CET

Impure copper containing Fe, Au, Ag as impurities is electrolytically refined. A current of 140 A for 482.5 s decreased the mass of the anode by 22.26 g and increased the mass of cathode by 22.011 g. Percentage of iron in impure copper is (Given; molar mass of Fe = 55.5 g mol, molar mass of Cu = 63.54 g mol)

Answer: (D)

Solution

Charge = 140 × 482.5 = 67550 C = 0.700 mol of electrons, i.e. 0.350 mol of dissolved at the anode; Cu deposited = 22.011/63.54 = 0.3464 mol, so Fe dissolved

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Question ID VK-066909