MHT CET Chemistry question

The correct representation of Nernst's equation for half-cell reaction Cu^{2+}(aq) + e^- \longrightarrow Cu^+(aq) is [MHTCET 2019]

(A)E^\circ_{Cu^+,Cu^{2+}} = E^\circ_{Cu^+,Cu^{2+}} - \dfrac{0.0592}{2}\log\dfrac{[Cu^+]}{[Cu^{2+}]}
(B)E_{Cu^+,Cu^{2+}} = E^\circ_{Cu^+,Cu^{2+}} - \dfrac{0.0592}{1}\log\dfrac{[Cu^+]}{[Cu^{2+}]}
(C)E^\circ_{Cu^+,Cu^{2+}} = E^\circ_{Cu^+,Cu^{2+}} - \dfrac{0.0592}{2}\log\dfrac{[Cu^+]}{[Cu^{2+}]}
(D)E_{Cu^+,Cu^{2+}} = E^\circ_{Cu^+,Cu^{2+}} - \dfrac{0.0592}{1}\log\dfrac{[Cu^+]}{[Cu^{2+}]}Correct

Answer: (D)

Solution

For , n = 1 and , so $E = E° -

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Question ID VK-066982