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MHT CET Physics question

PhysicsOscillationsMHT CET

If a particle is performing simple harmonic motion along X-axis with amplitude 4cm and time period 1.2 s. Then the minimum time taken by the particle to move from 2 cm to 4 cm and again back will be

Answer: (B)

Solution

From the mean position x = 2 cm occurs at T/12 and x = 4 cm at T/4, so 2 cm to 4 cm takes T/6 = 0.2 s and the return

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Question ID VK-067651