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MHT CET Physics question

PhysicsOscillationsMHT CET

The time period of S.H.M. is 16 seconds and it starts motion from the equilibrium position, after two seconds the velocity is m/s. Then the displacement amplitude is

Answer: (D)

Solution

= 2 /16 = /8 and v = A cos( t) with t = /4 at t = 2 s, so = A

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Question ID VK-067653