MHT CET Physics question
A particle is executing S.H.M. with amplitude of 4 cm and time period 12 sec. The time taken by the particle in going from its mean position to a position of displacement equal to 2 cm is . The time taken from this displaced position of 2 cm to reach the extreme position is . will be
Answer: (C)
Solution
y = 4 sin( t/6): y = 2 cm at t = 1 s so = 1 s, and y = 4 cm at t = 3 s so = 3 - 1 = 2 s, giving
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