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MHT CET Physics question

PhysicsOscillationsMHT CET

The displacement of a particle executing S.H.M. is given by y = 0.25 sin 200 t metre. The maximum speed to the particle and amplitude of the motion is

Answer: (B)

Solution

The amplitude is A = 0.25 m and = 200 rad/s, so = A = 0.25 200 = 50 m/s;

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Question ID VK-067664