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MHT CET Physics question

PhysicsOscillationsMHT CET

The time period of a particle undergoing S.H.M. is 16 s. It starts its motion from the mean position. After 2 s, its velocity is 0.4 m/s. Then the amplitude is

Answer: (A)

Solution

= /8 and v = A cos( t) = A (/8) cos(/4) = 0.4 gives A = 3.2

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Question ID VK-067665