Test SeriesFree PYQsExamsPricing

MHT CET Physics question

PhysicsOscillationsMHT CET

A particle executes simple harmonic motion with an amplitude of 4 cm. At the mean position, the velocity of the particle is 10 cm/s. The distance of the particle from the mean position when its speed becomes 5 cm/s is [EAMCET (Med.) 2000]

Answer: (C)

Solution

rad/s; \sqrt{16-x^2}x^2$=4⇒

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-068122