MHT CET Physics question
If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2 s, then its maximum velocity is [MHTCET 2009]
Answer: (B)
Solution
$ = Aω = 0.05 × (2π/2) = 0.05π ≈ 0.157\ \mathrm{m }≈
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account