The rate law for the reaction, RCl+NaOH_ (aq) ROH+NaCl is given by Rate =k[ RCl ] The rate of the reaction will be _______

MHT CET Chemistry question

The rate law for the reaction, \mathrm{RCl+NaOH_{(aq)}\to ROH+NaCl} is given by Rate The rate of the reaction will be

Answer: (B)

The rate depends only on [RCl] (first order), so halving [RCl] halves the rate; it is independent of NaOH concentration

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Question ID VK-069041