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MHT CET Chemistry question

ChemistryChemical KineticsMHT CET

The rate constants at 27°C and 67°C for the dissociation of are and respectively. What is the activation energy for the dissociation of ?

Answer: (A)

Solution

$=2.303R·=2.303×8.314×200×Missing argument for \dfrac\dfrac{300×340}

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Question ID VK-069057