MHT CET Chemistry question
The inversion of cane sugar is first order in [sugar] and proceeds with half-life of 600 min at pH = 4 for a given concentration of sugar. However, if pH = 5, the half-life changes to 60 min. The rate law expression for the sugar inversion can be written as
Answer: (D)
Solution
The reaction is first order in sugar, so where is the effective rate constant at a fixed pH; options (a), (b) and (c) make the rate rise steeply
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