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MHT CET Physics question

PhysicsWave OpticsMHT CET

In a single slit diffraction pattern, the distance between the first minimum on the left and the first minimum on the right is 5 mm. The screen on which the diffraction pattern is obtained is at a distance of 80 cm from the slit. The wavelength used is 6000Å. The width of the slit is [MHT-CET 2021]

Answer: (C)

Solution

mm gives \frac{2×0.8×6×10^{-7}}{5×10^{-3}}$=1.92×1

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Question ID VK-077512