In Young's double slit experiment, the wavelength of light used is 'λ'. The intensity at a point is 'I',...

Question

In Young's double slit experiment, the wavelength of light used is 'λ'. The intensity at a point is 'I', where the path-difference is 3 . If I_0 denotes the maximum intensity, the ratio I I_0 is ( 60^0= 1 2 = 30^0, 30^0= 3 2 = 60^0 ) [MHT-CET 2019]

Accepted Answer

(D)

MHT CET Physics question

Solution

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