MHT CET Physics question
A circular coil of radius 40 mm consists of 250 turns of wire in which the current is 20 mA. The magnetic field in the centre of the coil is
Answer: (A)
Solution
\dfrac{μ_0NI}{2r}\dfrac{4π×10^{-7}×250×0.02}{2×0.04}10^{-5}$
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account