MHT CET Physics question

Physics Moving Charges and Magnetism MHT CET

A 20 MeV proton is moving perpendicular to a uniform magnetic field of 2.5 T. The force on the proton is

(A) N
(B) N
(C) NCorrect
(D) N

Answer: (C)

Solution

J gives , so $F = qvB =

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Question ID VK-078572