MHT CET Physics question
A rectangular coil of area and 40 turns is pivoted about one of its vertical sides. The coil is in a horizontal field of 80 gauss. If a current of 0.20 mA produces an angular deflection of 20, then the torsional constant of the hair spring connected to the coil is (in Nm/degree)
Answer: (A)
Solution
\frac{NIAB}{θ}\frac{40×2×10^{-4}×5×10^{-4}×8×10^{-3}}{20}$ =
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